(4/x)^2=8/x^2

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Solution for (4/x)^2=8/x^2 equation: 



(4/x)^2=8/x^2

We move all terms to the left:

(4/x)^2-(8/x^2)=0



Domain of the equation: x)^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/x)^2-(8/x^2)=0

We get rid of parentheses

(+4/x)^2-8/x^2=0

We calculate fractions


((+4*x^2)/x^2*x^2)+(-8x)/x^2*x^2)=0



We calculate terms in parentheses: +((+4*x^2)/x^2*x^2), so:

(+4*x^2)/x^2*x^2

We multiply all the terms by the denominator


(+4*x^2)

We get rid of parentheses

4*x^2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)



We get rid of parentheses

4x^2-8x)/x^2*x^2=0

We multiply all the terms by the denominator


4x^2*x^2*x^2-8x)=0

Wy multiply elements

4x^6*x-8x)=0

We do not support expression: x^6

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